Question

A cationic colloidal electrolyte forms micelle at $10^{-4} M$ concentration in water. If $1 mm^{3}$ solution contains $10^{12}$ micelle structure, then the no. of cations involved in one micelle are $X\times 10$. Find the value of $X$.

Answer 1

No. of particles of cationic colloidal electrolyte/litre before micelle formation
$ = 10^{-4} \times 6 \times 10^{23} = 6 \times 10^{19}$
$\therefore $ No. of particles of cationic colloidal electrolyte/mm$^{3}$
$ = 6 \times 10^{19} \times 10^{-6} = 6 \times 10^{13}$
Number of micelles formed $ = 10^{12}$ /mm$^{3}$
$\therefore $ Number of cations in one micelle $= \frac{6 \times10^{13}}{10^{12}} = 60 $
$= 6\times10$