Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Physics
A cathode emits 1.8× 1014 electrons per second, when heated, when 400V is applied to anode all the emitted electrons reach the anode. The charge on electron is 1.6× 10- 19C . The maximum anode current is :-
Q. A cathode emits
1.8
×
1
0
14
electrons per second, when heated, when
400
V
is applied to anode all the emitted electrons reach the anode. The charge on electron is
1.6
×
1
0
−
19
C
. The maximum anode current is :-
543
168
NTA Abhyas
NTA Abhyas 2022
Report Error
A
27
μ
A
B
29
μ
A
C
72
μ
A
D
29
m
A
Solution:
i
=
t
Q
=
t
n
e
=
1.8
×
1
0
14
×
1.6
×
1
0
−
19
=
28.8
×
1
0
−
6
A
=
29
μ
A