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Q. A cathode emits $1.8\times 10^{14}$ electrons per second, when heated, when $400V$ is applied to anode all the emitted electrons reach the anode. The charge on electron is $1.6\times 10^{- 19}C$ . The maximum anode current is :-

NTA AbhyasNTA Abhyas 2022

Solution:

$i=\frac{Q}{t}=\frac{n e}{t}=1.8\times 10^{14}\times 1.6\times 10^{- 19}$
$=28.8\times 10^{- 6}A=29\mu A$