Question

A car of mass $m$ is taking a circular turn of radius $r$ on a frictional level road with a speed $v$. In order that the car does not skid ( $\mu =$ coefficient of friction)

• A. $\frac{m{v}^2}{r}\ge \mu mg$
• B. $\frac{m{v}^2}{r}\le \mu mg$
• C. $\frac{m{v}^2}{r}=\mu mg$
• D. $\frac{v}{r}=\mu g$

Answer 1

Answer: (B)

When a vehicle takes a turn on a circular path it requires centripetal force. If friction provides this centripetal force then vehicle can move in circular path safely.
ie. Friction force > Required centripetal force $\mu mg\ge \frac{m{v}^2}{r}$