Question

A car of mass $m$ is taking a circular turn of radius $r$ on a frictional level road with a speed $v$. In order that the car does not skid ( $ \mu = $ coefficient of friction)

• A. $ \frac{mv^{2}}{r}\ge \mu mg $
• B. $ \frac{mv^{2}}{r}\le \mu mg $
• C. $ \frac{mv^{2}}{r}=\mu mg $
• D. $ \frac{v}{r}=\mu g $

Answer 1

Answer: (B)

When a vehicle takes a turn on a circular path it requires centripetal force. If friction provides this centripetal force then vehicle can move in circular path safely.
ie. Friction force > Required centripetal force $ \mu mg\ge \frac{mv^{2}}{r} $