A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless road. If banking angle is 45°, the maximum speed of car is :-

Question

A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless road. If banking angle is 45°, the maximum speed of car is :- (A) 20 m/s (B) 30 m/s (C) 5 m/s (D) 10 m/s

Tardigrade Admin · Accepted Answer

tan θ=( v 2/ Rg ) tan 45°=( v 2/90 × 10) v =√900 =30 m / s

Q. A car of mass $1000 k g$ negotiates a banked curve of radius $90 m$ on a frictionless road. If banking angle is $4 5^{\circ}$ , the maximum speed of car is :-

20 m/s

30 m/s

5 m/s

10 m/s

$tan θ = \frac{v ^{2}}{R g}$
$tan 4 5^{\circ} = \frac{v ^{2}}{90 \times 10}$
$v = 900$
$= 30 m / s$

Q. A car of mass 1000kg negotiates a banked curve of radius 90m on a frictionless road. If banking angle is 45∘, the maximum speed of car is :-