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  4. A car of mass 1000 kg negotiates a banked curve of radius 90 m on a frictionless road. If banking angle is 45°, the maximum speed of car is :-

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Q. A car of mass $1000\, kg$ negotiates a banked curve of radius $90 \,m$ on a frictionless road. If banking angle is $45^{\circ}$, the maximum speed of car is :-

Solution:

$\tan \theta=\frac{ v ^{2}}{ Rg }$
$\tan 45^{\circ}=\frac{ v ^{2}}{90 \times 10}$
$v =\sqrt{900} $
$=30 \,m / s$