A car of mass 1000 kg is moving with a velocity of 15 m/s and it is acted upon by a forward force of 500 N due to engine and retarding force of 120 N due to friction. What will be its velocity after 10 seconds.?

Question

A car of mass 1000 kg is moving with a velocity of 15 m/s and it is acted upon by a forward force of 500 N due to engine and retarding force of 120 N due to friction. What will be its velocity after 10 seconds.? (A) 15 m/s (B) 16 m/s (C) 18.8 m/s (D) 20 m/s

Tardigrade Admin · Accepted Answer

m =1000 kg Forward force =500 N Backward force =120 N ∴ Net force (accelerating) =500-120 =380 N As, F = ma (380/1000)= a a =0.38 m / s 2 Now v=u+a t v=15+0.38 × 10=18.8 m / s 2

Q. A car of mass $1000 k g$ is moving with a velocity of $15 m / s$ and it is acted upon by a forward force of $500 N$ due to engine and retarding force of $120 N$ due to friction. What will be its velocity after 10 seconds.?

$15 m / s$

$16 m / s$

$18.8 m / s$

$20 m / s$

$m = 1000 k g$ Forward force $= 500 N$
Backward force $= 120 N$
$∴$ Net force (accelerating) $= 500 - 120$
$= 380 N$
As, $F = ma$
$\frac{380}{1000} = a$
$a = 0.38 m / s^{2}$
Now $v = u + a t$
$v = 15 + 0.38 \times 10 = 18.8 m / s^{2}$

Q. A car of mass 1000kg is moving with a velocity of 15m/s and it is acted upon by a forward force of 500N due to engine and retarding force of 120N due to friction. What will be its velocity after 10 seconds.?

15m/s

16m/s

18.8m/s

20m/s