A car is moving with a constant speed of 20 m / s in a circular horizontal track of radius 40 m. A bob is suspended from the roof of the car by a massless string. The angle made by the string with the vertical will be: (Take g=10 m / s 2 )

Question

A car is moving with a constant speed of 20 m / s in a circular horizontal track of radius 40 m. A bob is suspended from the roof of the car by a massless string. The angle made by the string with the vertical will be: (Take g=10 m / s 2 ) (A) (π/6) (B) (π/2) (C) (π/4) (D) (π/3)

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/bbcbb03d385a539539104ab75ffec273-.png" /> T sin θ=( mv2/ R ) tan θ=( v 2/ Rg ) tan θ=(202/40 × 10) tan θ=1 ⇒ θ=(π/4)

Q. A car is moving with a constant speed of $20 m / s$ in a circular horizontal track of radius $40 m$ . A bob is suspended from the roof of the car by a massless string. The angle made by the string with the vertical will be : (Take $g = 10 m / s^{2}$ )

$\frac{π}{6}$

$\frac{π}{2}$

$\frac{π}{4}$

$\frac{π}{3}$

$T sin θ = \frac{m v ^{2}}{R}$
$tan θ = \frac{v ^{2}}{R g}$
$tan θ = \frac{2 0 ^{2}}{40 \times 10}$
$tan θ = 1$
$\Rightarrow θ = \frac{π}{4}$

Q. A car is moving with a constant speed of 20m/s in a circular horizontal track of radius 40m. A bob is suspended from the roof of the car by a massless string. The angle made by the string with the vertical will be : (Take g=10m/s2 )

6π​

2π​

4π​

3π​