A car is moving on a horizontal circular track of radius 0.2 km with a constant speed. If coefficient of friction between tyres of car and road is 0.45, then speed of car may be [Take .g=10 m / s 2],

Question

A car is moving on a horizontal circular track of radius 0.2 km with a constant speed. If coefficient of friction between tyres of car and road is 0.45, then speed of car may be [Take .g=10 m / s 2], (A) 15 m / s (B) 30 m / s (C) 20 m / s (D) 40 m / s

Tardigrade Admin · Accepted Answer

(v2/r)=μ g (v2/0.2 × 103)=4.5 v=√900=30 m / s

Q. A car is moving on a horizontal circular track of radius $0.2 km$ with a constant speed. If coefficient of friction between tyres of car and road is $0.45$ , then speed of car may be [Take $g = 10 m / s^{2}]$ ,

15 m / s

30 m / s

20 m / s

40 m / s

$\frac{v ^{2}}{r} = μg$
$\frac{v ^{2}}{0.2 \times 1 0 ^{3}} = 4.5$
$v = 900 = 30 m / s$

Q. A car is moving on a horizontal circular track of radius 0.2km with a constant speed. If coefficient of friction between tyres of car and road is 0.45, then speed of car may be [Take g=10m/s2],