1. Tardigrade
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  3. Physics
  4. A car is moving on a horizontal circular track of radius 0.2 km with a constant speed. If coefficient of friction between tyres of car and road is 0.45, then speed of car may be [Take .g=10 m / s 2],

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Q. A car is moving on a horizontal circular track of radius $0.2\, km$ with a constant speed. If coefficient of friction between tyres of car and road is $0.45$, then speed of car may be [Take $\left.g=10\, m / s ^{2}\right]$,

Laws of Motion

Solution:

$\frac{v^{2}}{r}=\mu g$
$\frac{v^{2}}{0.2 \times 10^{3}}=4.5$
$v=\sqrt{900}=30\, m / s$