A car battery of e.m.f. 12 V and internal resistance 5 × 10-2 Ω receives a current of 60 A from an external source, then terminal potential difference of battery is :-

Question

A car battery of e.m.f. 12 V and internal resistance 5 × 10-2 Ω receives a current of 60 A from an external source, then terminal potential difference of battery is :- (A) 5V (B) 3V (C) 15V (D) 9V

Tardigrade Admin · Accepted Answer

text Here the terminal potential, V =12+ Ir =12+(60 × 5 × 10-1)=12+3=15 V

Q. A car battery of e.m.f. $12 V$ and internal resistance $5 \times 1 0^{- 2} Ω$ receives a current of $60 A$ from an external source, then terminal potential difference of battery is :-

5V

3V

15V

9V

$Here the terminal potential, V = 12 + I r = 12 + (60 \times 5 \times 1 0^{- 1}) = 12 + 3 = 15 V$

Q. A car battery of e.m.f. 12V and internal resistance 5×10−2Ω receives a current of 60A from an external source, then terminal potential difference of battery is :-

5V

3V

15V

9V

Here the terminal potential, V=12+Ir=12+(60×5×10−1)=12+3=15V

Q. A car battery of e.m.f. $12 V$ and internal resistance $5 \times 1 0^{- 2} Ω$ receives a current of $60 A$ from an external source, then terminal potential difference of battery is :-

$Here the terminal potential, V = 12 + I r = 12 + (60 \times 5 \times 1 0^{- 1}) = 12 + 3 = 15 V$