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Q. A car battery of e.m.f. $12 V$ and internal resistance $5 \times 10^{-2} \Omega$ receives a current of $60 A$ from an external source, then terminal potential difference of battery is :-

Current Electricity

Solution:

$\text { Here the terminal potential, } V =12+ Ir =12+\left(60 \times 5 \times 10^{-1}\right)=12+3=15 V$