A capillary tube of 2 mm diameter. What is the height to which water rises, if surface tension of water is 7.4 × 10-3 Nm -1 and angle of contact is 0° ?

Question

A capillary tube of 2 mm diameter. What is the height to which water rises, if surface tension of water is 7.4 × 10-3 Nm -1 and angle of contact is 0° ? (A) 0.25 mm (B) 1.51 mm (C) 0.4 mm (D) 0.5 mm

Tardigrade Admin · Accepted Answer

h =(2 S cos θ/ρ rg ) =(2 × 7.4 × 10-3 × cos 0°/103 × 10-3 × 9.8) =1.51 × 10-3=1.51 mm

Q. A capillary tube of $2 mm$ diameter. What is the height to which water rises, if surface tension of water is 7.4 $\times 1 0^{- 3} N m^{- 1}$ and angle of contact is $0^{\circ} ?$

$0.25 mm$

$1.51 mm$

$0.4 mm$

$0.5 mm$

$h = \frac{2 S c o s θ}{ρ r g}$
$= \frac{2 \times 7.4 \times 1 0 ^{- 3} \times c o s 0 ^{\circ}}{1 0 ^{3} \times 1 0 ^{- 3} \times 9.8}$
$= 1.51 \times 1 0^{- 3} = 1.51 mm$

Q. A capillary tube of 2mm diameter. What is the height to which water rises, if surface tension of water is 7.4 ×10−3Nm−1 and angle of contact is 0∘?

0.25mm

1.51mm

0.4mm

0.5mm