Question

A capillary tube of $2 mm$ diameter. What is the height to which water rises, if surface tension of water is 7.4 $\times 10^{-3} Nm ^{-1}$ and angle of contact is $0^{\circ} ?$

• A. $0.25 mm$
• B. $1.51 mm$
• C. $0.4 mm$
• D. $0.5 mm$

Answer 1

Answer: (B)

$h =\frac{2 S \cos \theta}{\rho rg }$
$=\frac{2 \times 7.4 \times 10^{-3} \times \cos 0^{\circ}}{10^{3} \times 10^{-3} \times 9.8}$
$=1.51 \times 10^{-3}=1.51\,mm$