Question

A capacitor of capacitance $6\mu F$ is charged upto $100V$. The energy stored in the capacitor is :

• A. 0.6 J
• B. 0.06 J
• C. 0.03 J
• D. 0.3 J

Answer 1

Answer: (C)

The energy stored in the capacitor is given by
$U=\frac{1}{2}C{V}^2$
Given, $C=6\times 10^{-6}F,V=100V$
So, $U=\frac{1}{2}\times 6\times 10^{-6}\times (100{)}^2$
$=3\times 10^{-2}J=0.03J$