Thank you for reporting, we will resolve it shortly
Q.
A capacitor of capacitance $6\, \mu F$ is charged upto $100\, V$. The energy stored in the capacitor is :
ManipalManipal 2006Electrostatic Potential and Capacitance
Solution:
The energy stored in the capacitor is given by
$U=\frac{1}{2} C V^{2}$
Given, $C=6 \times 10^{-6} F,\, V=100\, V$
So, $U =\frac{1}{2} \times 6 \times 10^{-6} \times(100)^{2}$
$=3 \times 10^{-2} J =0.03\, J$