A capacitor of 8F is connected as shown in the figure. Charge on the plates of the capacitor

Question

A capacitor of 8F is connected as shown in the figure. Charge on the plates of the capacitor <img class="img-fluid question-image" alt="Question" src="https://cdn.tardigrade.in/q/nta/p-i7nkwnegptd43v7p.jpg" /> (A) 32 C (B) 40 C (C) 0 C (D) 80 C

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="Solution" src="https://cdn.tardigrade.in/q/nta/p-i7nkwnegptd4f2qn.jpg" /> When the capacitor completely charged, there is no current passes through it. Current exists only in other branch. I=(V/Re q)=(5/1 + 4)= 1A The potential difference across capacitor =5-1=4 V Charge stored in capacitor, q =C× V=8× 4=32C

Q. A capacitor of $8 F$ is connected as shown in the figure. Charge on the plates of the capacitor

$32 C$

$40 C$

$0 C$

$80 C$

When the capacitor completely charged, there is no current passes through it. Current exists only in other branch.
$I = \frac{V}{R _{e q}} = \frac{5}{1 + 4} = 1 A$
The potential difference across capacitor $= 5 - 1 = 4 V$
Charge stored in capacitor, $q$
$= C \times V = 8 \times 4 = 32 C$

Q. A capacitor of 8F is connected as shown in the figure. Charge on the plates of the capacitor

32C

40C

0C

80C