A capacitor of 8 F is connected as shown. Charge on the plates of the capacitor

Question

A capacitor of 8 F is connected as shown. Charge on the plates of the capacitor (A) 32 C (B) 40 C (C) 0 C (D) 80 C

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/a77b0a71e204c94c04e644d47f310398-.png" /> When the capacitor completely charged, there is no current passes through it. Current exists only in other branch. I=(V/R eq )=(5/1+4)=1 A The potential difference across capacitor =5-1 × 1=5-1=4 V Charge stored in capacitor, q =C × V=8 × 4=32 C

Q. A capacitor of 8F is connected as shown. Charge on the plates of the capacitor

32 C

40 C

0 C

80 C

When the capacitor completely charged, there is no current passes through it. Current exists only in other branch. I=Req​V​=1+45​=1A The potential difference across capacitor =5−1×1=5−1=4V Charge stored in capacitor, q =C×V=8×4=32C

Q. A capacitor of $8 F$ is connected as shown. Charge on the plates of the capacitor