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Q.
A capacitor of $8\,F$ is connected as shown. Charge on the plates of the capacitor
KCETKCET 2016Electrostatic Potential and Capacitance
Solution:
When the capacitor completely charged, there is no current passes through it. Current exists only in other branch.
$I=\frac{V}{R_{ eq }}=\frac{5}{1+4}=1\, A$
The potential difference across
capacitor $=5-1 \times 1=5-1=4\, V$
Charge stored in capacitor, $q$
$=C \times V=8 \times 4=32\, C$