A capacitor is connected to 10 V battery. The charge on plates is 40 μ C. If medium between plates is air. The charge on plates will become 100 μ C if the space between the plates is filled with oil. The dielectric constant of oil is:

Question

A capacitor is connected to 10 V battery. The charge on plates is 40 μ C. If medium between plates is air. The charge on plates will become 100 μ C if the space between the plates is filled with oil. The dielectric constant of oil is: (A) 2.5 (B) 4 (C) 6.25 (D) 10

Tardigrade Admin · Accepted Answer

After filling the space with oil C'=ϵr C and Q'=Q ϵr ϵr=(Q'/Q)=(100/40)=2.5

Q. A capacitor is connected to $10 V$ battery. The charge on plates is $40 μ C$ . If medium between plates is air. The charge on plates will become $100 μ C$ if the space between the plates is filled with oil. The dielectric constant of oil is:

$2.5$

$4$

$6.25$

$10$

After filling the space with oil
$C^{'} = ϵ_{r} C$ and $Q^{'} = Q ϵ_{r}$
$ϵ_{r} = \frac{Q ^{'}}{Q} = \frac{100}{40} = 2.5$

Q. A capacitor is connected to 10V battery. The charge on plates is 40μC. If medium between plates is air. The charge on plates will become 100μC if the space between the plates is filled with oil. The dielectric constant of oil is:

2.5

4

6.25

10

After filling the space with oil C′=ϵr​C and Q′=Qϵr​ ϵr​=QQ′​=40100​=2.5

Q. A capacitor is connected to $10 V$ battery. The charge on plates is $40 μ C$ . If medium between plates is air. The charge on plates will become $100 μ C$ if the space between the plates is filled with oil. The dielectric constant of oil is:

$2.5$

$4$

$6.25$

$10$

After filling the space with oil
$C^{'} = ϵ_{r} C$ and $Q^{'} = Q ϵ_{r}$
$ϵ_{r} = \frac{Q ^{'}}{Q} = \frac{100}{40} = 2.5$