Q.
A capacitor connected to a 10V battery collects a charge of 40μC with air as dielectric and 100μC with a given oil as dielectric. The dielectric constant of the oil is
906
206
Electrostatic Potential and Capacitance
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Solution:
q=CV, As V is constant, therefore q∝C.
Here, C becomes 40100=2.5 times ∴K=2.5