A bullet of mass 50 g is fired from a 5 kg gun with a velocity of 1 km/sec. The speed of recoil of the gun is:

Question

A bullet of mass 50 g is fired from a 5 kg gun with a velocity of 1 km/sec. The speed of recoil of the gun is: (A) 5 m/s (B) 1 m/s (C) 0.5 m/s (D) 10 m/s

Tardigrade Admin · Accepted Answer

Applying law of conservation or momentum mv text = text m upsilon Here, mass of bullet m=50 text g=0.05 text kg velocity of bullet =1 text km text/sec=1000 text m text/sec mass of gun m=5kg or 0.05× 1000=5v or v=(0.05× 1000/5) so, v=10 m text/s

Q. A bullet of mass 50 g is fired from a 5 kg gun with a velocity of 1 km/sec. The speed of recoil of the gun is:

5 m/s

1 m/s

0.5 m/s

10 m/s

Applying law of conservation or momentum $m v = m υ$ Here, mass of bullet $m = 50 g = 0.05 k g$ velocity of bullet $= 1 km / sec = 1000 m / sec$ mass of gun $m = 5 k g$ or $0.05 \times 1000 = 5 v$ or $v = \frac{0.05 \times 1000}{5}$ so, $v = 10 m / s$

Q. A bullet of mass 50 g is fired from a 5 kg gun with a velocity of 1 km/sec. The speed of recoil of the gun is:

5 m/s

1 m/s

0.5 m/s

10 m/s

Applying law of conservation or momentum mv=mυ Here, mass of bullet m=50g=0.05kg velocity of bullet =1km/sec=1000m/sec mass of gun m=5kg or 0.05×1000=5v or v=50.05×1000​ so, v=10m/s

Applying law of conservation or momentum $m v = m υ$ Here, mass of bullet $m = 50 g = 0.05 k g$ velocity of bullet $= 1 km / sec = 1000 m / sec$ mass of gun $m = 5 k g$ or $0.05 \times 1000 = 5 v$ or $v = \frac{0.05 \times 1000}{5}$ so, $v = 10 m / s$