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Q. A bullet of mass 50 g is fired from a 5 kg gun with a velocity of 1 km/sec. The speed of recoil of the gun is:

JIPMERJIPMER 1999

Solution:

Applying law of conservation or momentum $ mv\text{ }=\text{ }m\upsilon $ Here, mass of bullet $ m=50\text{ }g=0.05\text{ }kg $ velocity of bullet $ =1\text{ }km\text{/}sec=1000\text{ }m\text{/}sec $ mass of gun $ m=5kg $ or $ 0.05\times 1000=5v $ or $ v=\frac{0.05\times 1000}{5} $ so, $ v=10\,m\text{/}s $