A bullet of mass 0.1 kg is fired with a speed of 100 m/s . The mass of gun being 50 kg . Then the velocity of recoil become

Question

A bullet of mass 0.1 kg is fired with a speed of 100 m/s . The mass of gun being 50 kg . Then the velocity of recoil become (A) 0.05 m/s (B) 0.5 m/s (C) 0.1 m/s (D) 0.2 m/s

Tardigrade Admin · Accepted Answer

From law of conservation of momentum total initial momentum = total final momentum m1 u1+m2 u2 =m1 v1+m2 v2 0.1 × 0+50 × 0 =0.1 × 100+50(-v2) 0 =10-50 v2 v2 =(10/50)=0.2 m / s

Q. A bullet of mass $0.1 k g$ is fired with a speed of $100 m / s$ . The mass of gun being $50 k g$ . Then the velocity of recoil become

0.05 m/s

0.5 m/s

0.1 m/s

0.2 m/s

From law of conservation of momentum total initial momentum = total final momentum
$m_{1} u_{1} + m_{2} u_{2}$
$= m_{1} v_{1} + m_{2} v_{2}$
$0.1 \times 0 + 50 \times 0$
$= 0.1 \times 100 + 50 (- v_{2})$
$0 = 10 - 50 v_{2}$
$v_{2} = \frac{10}{50} = 0.2 m / s$

Q. A bullet of mass 0.1kg is fired with a speed of 100m/s . The mass of gun being 50kg . Then the velocity of recoil become