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Q.
A bullet of mass $0.1\,kg $ is fired with a speed of $100\,m/s $ . The mass of gun being $50\,kg$ . Then the velocity of recoil become
Punjab PMETPunjab PMET 2005Laws of Motion
Solution:
From law of conservation of momentum total initial momentum = total final momentum
$m_{1} u_{1}+m_{2} u_{2}$
$=m_{1} v_{1}+m_{2} v_{2}$
$0.1 \times 0+50 \times 0$
$=0.1 \times 100+50\left(-v_{2}\right)$
$0 =10-50\, v_{2}$
$v_{2} =\frac{10}{50}=0.2\, m / s$