A bullet of mass 0.05 kg moving with a speed of 80 text ms-1 enters a wooden block and is stopped after a distance of 0.40 m . The average resistive force exerted by the block on the bellow is

Question

A bullet of mass 0.05 kg moving with a speed of 80 text ms-1 enters a wooden block and is stopped after a distance of 0.40 m . The average resistive force exerted by the block on the bellow is (A) 300 N (B) 20 N (C) 400 N (D) 40 N

Tardigrade Admin · Accepted Answer

Resistive force ( textinitial textkineticd textenergy/ textstopping textdistance) =((1/2)× 0.05× (80)2/0.40)=400 N

Q. A bullet of mass $0.05 k g$ moving with a speed of $80 m s^{- 1}$ enters a wooden block and is stopped after a distance of $0.40 m$ . The average resistive force exerted by the block on the bellow is

300 N

20 N

400 N

40 N

200 N

Resistive force $\frac{initial kineticd energy}{stopping distance}$
$= \frac{\frac{1}{2} \times 0.05 \times ( 80 ) ^{2}}{0.40} = 400 N$

Q. A bullet of mass 0.05kg moving with a speed of 80ms−1 enters a wooden block and is stopped after a distance of 0.40m . The average resistive force exerted by the block on the bellow is