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Q. A bullet of mass $ 0.05\, kg $ moving with a speed of $ 80\text{ }m{{s}^{-1}} $ enters a wooden block and is stopped after a distance of $ 0.40\, m $ . The average resistive force exerted by the block on the bellow is

KEAMKEAM 2008Laws of Motion

Solution:

Resistive force $ \frac{\text{initial}\,\text{kineticd}\,\text{energy}}{\text{stopping}\,\text{distance}} $
$ =\frac{\frac{1}{2}\times 0.05\times {{(80)}^{2}}}{0.40}=400\,N $