A bulb was heated from 27° C to 227° C at constant ' pressure. Calculate the volume of bulb if 200 ml of air measured at 27° C was expelled during process

Question

A bulb was heated from 27° C to 227° C at constant ' pressure. Calculate the volume of bulb if 200 ml of air measured at 27° C was expelled during process (A) 300 ml (B) 400 ml (C) 500 ml (D) 350 ml

Tardigrade Admin · Accepted Answer

Let volume of bulb be V ml Volume of air at 300 K given out =200 ml. Volume of air at 500 K given out: (V1/T1)=(V2/T2) or (200/300)=(V2/500) Or, V2=(100000/300) Volume of air at 500 K =(100000/300) Therefore, again using eq. (V/300)=(V+(100000/300)/500) V=500 ml

Q. A bulb was heated from $2 7^{\circ} C$ to $22 7^{\circ} C$ at constant ' pressure. Calculate the volume of bulb if $200 m l$ of air measured at $2 7^{\circ} C$ was expelled during process

$300 m l$

$400 m l$

$500 m l$

$350 m l$

Q. A bulb was heated from 27∘C to 227∘C at constant ' pressure. Calculate the volume of bulb if 200ml of air measured at 27∘C was expelled during process

300ml

400ml

500ml

350ml

Let volume of bulb be Vml Volume of air at 300K given out =200ml. Volume of air at 500K given out: T1​V1​​=T2​V2​​ or 300200​=500V2​​ Or, V2​=300100000​ Volume of air at 500K=300100000​ Therefore, again using eq. 300V​=500V+300100000​​ V=500ml

Q. A bulb was heated from $2 7^{\circ} C$ to $22 7^{\circ} C$ at constant ' pressure. Calculate the volume of bulb if $200 m l$ of air measured at $2 7^{\circ} C$ was expelled during process

$300 m l$

$400 m l$

$500 m l$

$350 m l$