Question

A bulb was heated from $27^{\circ} C$ to $227^{\circ} C$ at constant ' pressure. Calculate the volume of bulb if $200 \,ml$ of air measured at $27^{\circ} C$ was expelled during process

• A. $300\, ml$
• B. $400\, ml$
• C. $500\, ml$
• D. $350\, ml$

Answer 1

Answer: (C)

Let volume of bulb be $V\, ml$
Volume of air at $300\, K$ given out $=200\, ml$.
Volume of air at $500\, K$ given out: $\frac{V_{1}}{T_{1}}=\frac{V_{2}}{T_{2}}$
or $\frac{200}{300}=\frac{V_{2}}{500} $
Or, $ V_{2}=\frac{100000}{300}$
Volume of air at $500 \,K =\frac{100000}{300}$
Therefore, again using eq.
$\frac{V}{300}=\frac{V+\frac{100000}{300}}{500}$
$V=500\, ml$