A bulb is emitted electromagnetic radiation of 660 nm wave length. The Total energy of radiation is 3 x 10-18 J The number of emitted photon will be: (h = 6.6 × 10-34 Js, C = 3×108 m/s)

Question

A bulb is emitted electromagnetic radiation of 660 nm wave length. The Total energy of radiation is 3 x 10-18 J The number of emitted photon will be: (h = 6.6 × 10-34 Js, C = 3×108 m/s) (A) 1 (B) 10 (C) 100 (D) 1000

Tardigrade Admin · Accepted Answer

Number of photons = n E =(hc/λ) 3×10-18=(6.6×10-34×3×108× n/660×10-9) n=(30/3)=10

Q. A bulb is emitted electromagnetic radiation of 660 nm wave length. The Total energy of radiation is 3 x 10^-18 J The number of emitted photon will be : (h = 6.6 × 10^-34 Js, C = 3×10⁸ m/s)

1

10

100

1000

Number of photons = n
E $= \frac{h c}{λ}$
$3 \times 1 0^{- 18} = \frac{6.6 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8} \times n}{660 \times 1 0 ^{- 9}}$
$n = \frac{30}{3} = 10$

Q. A bulb is emitted electromagnetic radiation of 660 nm wave length. The Total energy of radiation is 3 x 10-18 J The number of emitted photon will be : (h = 6.6 × 10-34 Js, C = 3×108 m/s)

1

10

100

1000

Number of photons = n E =λhc​ 3×10−18=660×10−96.6×10−34×3×108×n​ n=330​=10

Q. A bulb is emitted electromagnetic radiation of 660 nm wave length. The Total energy of radiation is 3 x 10^-18 J The number of emitted photon will be : (h = 6.6 × 10^-34 Js, C = 3×10⁸ m/s)

Number of photons = n
E $= \frac{h c}{λ}$
$3 \times 1 0^{- 18} = \frac{6.6 \times 1 0 ^{- 34} \times 3 \times 1 0 ^{8} \times n}{660 \times 1 0 ^{- 9}}$
$n = \frac{30}{3} = 10$