A bulb and a capacitor are in series with an A C source. On increasing frequency, how will glow of the bulb change?

Question

A bulb and a capacitor are in series with an A C source. On increasing frequency, how will glow of the bulb change? (A) The glow decreases. (B) The glow increases. (C) The glow remain the same. (D) The bulb quenches.

Tardigrade Admin · Accepted Answer

When frequency v is increased, the capacitive reactance, XC=(1/2 π v C), decreases and hence the current through the bulb increases. This will increase the brightness of the bulb.

Q. A bulb and a capacitor are in series with an $A C$ source. On increasing frequency, how will glow of the bulb change?

The glow decreases.

The glow increases.

The glow remain the same.

The bulb quenches.

When frequency $v$ is increased, the capacitive reactance, $X_{C} = \frac{1}{2 π v C}$ , decreases and hence the current through the bulb increases. This will increase the brightness of the bulb.

Q. A bulb and a capacitor are in series with an AC source. On increasing frequency, how will glow of the bulb change?