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Q.
A bulb and a capacitor are in series with an $A C$ source. On increasing frequency, how will glow of the bulb change?
Alternating Current
Solution:
When frequency $v$ is increased, the capacitive reactance, $X_{C}=\frac{1}{2 \pi v C}$, decreases and hence the current through the bulb increases. This will increase the brightness of the bulb.