A bucket tied at the end of a 1.6 m long string is whirled in a vertical circle with constant speed. What should be the minimum speed so that the water from the bucket does not spill when the bucket is at the highest position?

Question

A bucket tied at the end of a 1.6 m long string is whirled in a vertical circle with constant speed. What should be the minimum speed so that the water from the bucket does not spill when the bucket is at the highest position? (A) 4 m / sec (B) 6.25 m / sec (C) 16 m / sec (D) None of these

Tardigrade Admin · Accepted Answer

Since water does not fall down, therefore the velocity of revolution should be just sufficient to provide centripetal acceleration at the top of vertical circle. So,

v = (g r) = {10 \times (1.6)} = (16) = 4 m / sec

Q. A bucket tied at the end of a $1.6 m$ long string is whirled in a vertical circle with constant speed. What should be the minimum speed so that the water from the bucket does not spill when the bucket is at the highest position?

$4 m / sec$

$6.25 m / sec$

$16 m / sec$

None of these

Since water does not fall down, therefore the velocity of revolution should be just sufficient to provide centripetal acceleration at the top of vertical circle. So,
$v = (g r) = {10 \times (1.6)} = (16) = 4 m / sec$

Q. A bucket tied at the end of a 1.6m long string is whirled in a vertical circle with constant speed. What should be the minimum speed so that the water from the bucket does not spill when the bucket is at the highest position?

4m/sec

6.25m/sec

16m/sec