1. Tardigrade
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  3. Physics
  4. A bucket tied at the end of a 1.6 m long string is whirled in a vertical circle with constant speed. What should be the minimum speed so that the water from the bucket does not spill when the bucket is at the highest position?

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Q. A bucket tied at the end of a $1.6\, m$ long string is whirled in a vertical circle with constant speed. What should be the minimum speed so that the water from the bucket does not spill when the bucket is at the highest position?

Work, Energy and Power

Solution:

Since water does not fall down, therefore the velocity of revolution should be just sufficient to provide centripetal acceleration at the top of vertical circle. So,
$v =\sqrt{( gr )}=\sqrt{\{10 \times(1.6)\}}=\sqrt{(16)}=4\, m / \sec$