Tardigrade
Tardigrade - CET NEET JEE Exam App
Exams
Login
Signup
Tardigrade
Question
Chemistry
A brown ring is formed in the ring test for NO 3-ion. It is due to the formation of
Q. A brown ring is formed in the ring test for
N
O
3
−
ion. It is due to the formation of
1742
218
Report Error
A
[
F
e
(
H
2
O
)
5
(
NO
)
]
2
+
100%
B
F
e
S
O
4
⋅
N
O
2
0%
C
[
F
e
(
H
2
O
)
4
(
NO
)
2
]
2
+
0%
D
F
e
S
O
4
⋅
H
N
O
3
0%
Solution:
Correct answer is (a)
[
F
e
(
H
2
O
)
5
(
NO
)
]
2
+