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Chemistry
A brown ring is formed in the ring test for NO 3-ion. It is due to the formation of
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Q. A brown ring is formed in the ring test for $NO _{3}^{-}$ion. It is due to the formation of
A
$\left[ Fe \left( H _{2} O \right)_{5}( NO )\right]^{2+}$
100%
B
$FeSO _{4} \cdot NO _{2}$
0%
C
$\left[ Fe \left( H _{2} O \right)_{4}( NO )_{2}\right]^{2+}$
0%
D
$FeSO _{4} \cdot HNO _{3}$
0%
Solution:
Correct answer is (a) $\left[ Fe \left( H _{2} O \right)_{5}( NO )\right]^{2+}$