A bromoalkane X reacts with magnesium in dry ether to form compound Y . The reaction of Y with methanal followed by hydrolysis yield an alcohol having molecular formula C4H10O . The compound X is:

Question

A bromoalkane X reacts with magnesium in dry ether to form compound Y . The reaction of Y with methanal followed by hydrolysis yield an alcohol having molecular formula C4H10O . The compound X is: (A) bromo ethane (B) bromo methane (C) 1-bromo propane (D) 2-bromo propane

Tardigrade Admin · Accepted Answer

underset1- textbromopropeneCH3 - CH2 - CH2 - Br + Mg ->[ textdry][ textether] CH3CH2CH2MgBr ->[HCHO] CH3CH2CH2CH2 - O - MgBr

Q. A bromoalkane $X$ reacts with magnesium in dry ether to form compound $Y$ . The reaction of $Y$ with methanal followed by hydrolysis yield an alcohol having molecular formula $C_{4} H_{10} O$ . The compound $X$ is:

bromo ethane

bromo methane

1-bromo propane

2-bromo propane

$1 - bromopropene C H_{3} - C H_{2} - C H_{2} - B r + M g$
$dry ether C H_{3} C H_{2} C H_{2} M g B r$

$HCHO C H_{3} C H_{2} C H_{2} C H_{2} - O - M g B r$

Q. A bromoalkane X reacts with magnesium in dry ether to form compound Y . The reaction of Y with methanal followed by hydrolysis yield an alcohol having molecular formula C4​H10​O . The compound X is: