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  3. Chemistry
  4. A bromoalkane X reacts with magnesium in dry ether to form compound Y . The reaction of Y with methanal followed by hydrolysis yield an alcohol having molecular formula C4H10O . The compound X is:

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Q. A bromoalkane $ X $ reacts with magnesium in dry ether to form compound $ Y $ . The reaction of $ Y $ with methanal followed by hydrolysis yield an alcohol having molecular formula $ {{C}_{4}}{{H}_{10}}O $ . The compound $ X $ is:

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Solution:

$\underset{1- \text{bromopropene}}{CH_3 - CH_2 - CH_2 - Br + Mg}$
$\ce{->[\text{dry}][\text{ether}]} CH_3CH_2CH_2MgBr$

$\ce{->[HCHO]} CH_3CH_2CH_2CH_2 - O - MgBr$

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