A boy of 50 kg is standing in a lift moving down with an acceleration 9.8 m/s2 . The apparent weight of the boy will be

Question

A boy of 50 kg is standing in a lift moving down with an acceleration 9.8 m/s2 . The apparent weight of the boy will be (A)  50/9.8 N  (B)  50× 9.8 N  (C)  50 N  (D)  zero

Tardigrade Admin · Accepted Answer

Mass of the boy m=50 kg Downwards acceleration of lift a=9.8 m/s2 Apparent weight of the boy when the lift is moving downwards is given by W=m(g-a)=50(9.8-9.8)=0

Q. A boy of $50 k g$ is standing in a lift moving down with an acceleration $9.8 m / s^{2}$ . The apparent weight of the boy will be

$50/9.8 N$

$50 \times 9.8 N$

$50 N$

$zero$

Mass of the boy $m = 50 k g$ Downwards acceleration of lift $a = 9.8 m / s^{2}$ Apparent weight of the boy when the lift is moving downwards is given by $W = m (g - a) = 50 (9.8 - 9.8) = 0$

Q. A boy of 50kg is standing in a lift moving down with an acceleration 9.8m/s2 . The apparent weight of the boy will be

50/9.8N

50×9.8N

50N

zero