A box is lying on an inclined plane. If the box starts sliding when the angle of inclination is 45° , then its coefficient of friction will be:

Question

A box is lying on an inclined plane. If the box starts sliding when the angle of inclination is 45° , then its coefficient of friction will be: (A) 1 (B) 2 (C)  √3  (D)  (√3/2)

Tardigrade Admin · Accepted Answer

The angle of inclination θ =45° The coefficient of static friction is given by μ = tan θ = tan 45° =1

Q. A box is lying on an inclined plane. If the box starts sliding when the angle of inclination is $4 5^{\circ},$ then its coefficient of friction will be:

$1$

$2$

$3$

$\frac{3}{2}$

The angle of inclination $θ = 4 5^{\circ}$
The coefficient of static friction is given by
$μ = tan θ = tan 4 5^{\circ} = 1$

Q. A box is lying on an inclined plane. If the box starts sliding when the angle of inclination is 45∘, then its coefficient of friction will be:

1

2

3​

23​​

The angle of inclination θ=45∘ The coefficient of static friction is given by μ=tanθ=tan45∘=1

Q. A box is lying on an inclined plane. If the box starts sliding when the angle of inclination is $4 5^{\circ},$ then its coefficient of friction will be:

$1$

$2$

$3$

$\frac{3}{2}$

The angle of inclination $θ = 4 5^{\circ}$
The coefficient of static friction is given by
$μ = tan θ = tan 4 5^{\circ} = 1$