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  4. A box is lying on an inclined plane. If the box starts sliding when the angle of inclination is 45° , then its coefficient of friction will be:

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Q. A box is lying on an inclined plane. If the box starts sliding when the angle of inclination is $ 45^{\circ} , $ then its coefficient of friction will be:

Uttarkhand PMTUttarkhand PMT 2005

Solution:

The angle of inclination $ \theta =45^{\circ} $
The coefficient of static friction is given by
$ \mu =\tan \theta =\tan 45^{\circ} =1 $