A bomb is dropped on an enemy post by an aeroplane flying horizontally with a velocity of 60 km h -1 and at a height of 490 m. At the time of dropping the bomb, how far the aeroplane should be from the enemy post so that the bomb may directly hit the target?

Question

A bomb is dropped on an enemy post by an aeroplane flying horizontally with a velocity of 60 km h -1 and at a height of 490 m. At the time of dropping the bomb, how far the aeroplane should be from the enemy post so that the bomb may directly hit the target? (A) (400/3) m (B) (500/3) m (C) (1700/3) m (D) 498 m

Tardigrade Admin · Accepted Answer

<img class="img-fluid question-image" alt="image" src="https://cdn.tardigrade.in/img/question/physics/281042c183d9caab1074041cf8036baf-.png" /> Let t be the time taken by the bomb to hit the target. ∴ t =√(2 h/g)=√(2 × 490/9.8) s =√100 s =10 s x =u t=(60 × (5/18)) m s -1 × 10 s =(500/3) m

Q. A bomb is dropped on an enemy post by an aeroplane flying horizontally with a velocity of $60 km h^{- 1}$ and at a height of $490 m$ . At the time of dropping the bomb, how far the aeroplane should be from the enemy post so that the bomb may directly hit the target?

$\frac{400}{3} m$

$\frac{500}{3} m$

$\frac{1700}{3} m$

$498 m$

Let $t$ be the time taken by the bomb to hit the target.
$∴ t = \frac{2 h}{g} = \frac{2 \times 490}{9.8} s = 100 s = 10 s$
$x = u t = (60 \times \frac{5}{18}) m s^{- 1} \times 10 s = \frac{500}{3} m$

Q. A bomb is dropped on an enemy post by an aeroplane flying horizontally with a velocity of 60kmh−1 and at a height of 490m. At the time of dropping the bomb, how far the aeroplane should be from the enemy post so that the bomb may directly hit the target?

3400​m

3500​m

31700​m

498m