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Q. A bomb is dropped on an enemy post by an aeroplane flying horizontally with a velocity of $60 \,km \,h ^{-1}$ and at a height of $490 \,m$. At the time of dropping the bomb, how far the aeroplane should be from the enemy post so that the bomb may directly hit the target?

Motion in a Plane

Solution:

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Let $t$ be the time taken by the bomb to hit the target.
$\therefore t =\sqrt{\frac{2 h}{g}}=\sqrt{\frac{2 \times 490}{9.8}} s =\sqrt{100} s =10 s $
$x =u t=\left(60 \times \frac{5}{18}\right) m s ^{-1} \times 10 s =\frac{500}{3} m$