A body travelling with uniform acceleration crosses two points A and B with velocities 20 ms-1 and 30 ms-1 respectively. The speed of the body at the mid-point of A and B is nearest to

Question

A body travelling with uniform acceleration crosses two points A and B with velocities 20 ms-1 and 30 ms-1 respectively. The speed of the body at the mid-point of A and B is nearest to (A)  25.5 ms-1  (B)  25 ms-1  (C)  24 text ms-1  (D)  10√6 ms-1

Tardigrade Admin · Accepted Answer

A particle moving with uniform acceleration from A to B along straight line has velocities

v_{1}

and

v_{2}

at A and B respectively. If C is the midpoint between A and B then velocity of the particle at C.

v = \frac{v _{1}^{2} + v _{2}^{2}}{2}

= \frac{( 20 ) ^{2} + ( 30 ) ^{2}}{2}

= \frac{400 + 900}{2} = 650

= 25.5 m s^{- 1}

Q. A body travelling with uniform acceleration crosses two points $A$ and $B$ with velocities $20 m s^{- 1}$ and $30 m s^{- 1}$ respectively. The speed of the body at the mid-point of $A$ and $B$ is nearest to

$25.5 m s^{- 1}$

$25 m s^{- 1}$

$24 m s^{- 1}$

$106 m s^{- 1}$

$22 m s^{- 1}$

Q. A body travelling with uniform acceleration crosses two points A and B with velocities 20ms−1 and 30ms−1 respectively. The speed of the body at the mid-point of A and B is nearest to

25.5ms−1

25ms−1

24ms−1

106​ms−1

22ms−1