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Q.
A body travelling with uniform acceleration crosses two points $A$ and $B$ with velocities $ 20\,m{{s}^{-1}} $ and $ 30\,m{{s}^{-1}} $ respectively. The speed of the body at the mid-point of $A$ and $B$ is nearest to
A particle moving with uniform acceleration from A to B along straight line has velocities $ {{v}_{1}} $ and $ {{v}_{2}} $ at A and B respectively. If C is the midpoint between A and B then velocity of the particle at C.
$ v=\sqrt{\frac{v_{1}^{2}+v_{2}^{2}}{2}} $
$ =\sqrt{\frac{{{(20)}^{2}}+{{(30)}^{2}}}{2}} $
$ =\sqrt{\frac{400+900}{2}}=\sqrt{650} $
$ =25.5\text{ }m{{s}^{-1}} $