A body starting from rest moves with uniform acceleration. The distance covered by the body in time t is proportional to

Question

A body starting from rest moves with uniform acceleration. The distance covered by the body in time t is proportional to (A)  √t  (B)  t3/2  (C)  t2/3  (D)  t3

Tardigrade Admin · Accepted Answer

The distance covered by a body moving with uniform acceleration is given by s=ut+(1/2)at2 As body starts from rest, therefore initial velocity u = 0 ∴ Distance covered by the body s=(1/2)at2 or s propto t2

Q. A body starting from rest moves with uniform acceleration. The distance covered by the body in time t is proportional to

$t$

$t^{3/2}$

$t^{2/3}$

$t^{3}$

The distance covered by a body moving with uniform acceleration is given by $s = u t + \frac{1}{2} a t^{2}$ As body starts from rest, therefore initial velocity u = 0 $∴$ Distance covered by the body $s = \frac{1}{2} a t^{2}$ or $s \propto t^{2}$

Q. A body starting from rest moves with uniform acceleration. The distance covered by the body in time t is proportional to

t​

t3/2

t2/3

t3

The distance covered by a body moving with uniform acceleration is given by s=ut+21​at2 As body starts from rest, therefore initial velocity u = 0 ∴ Distance covered by the body s=21​at2 or s∝t2

$t$

$t^{3/2}$

$t^{2/3}$

$t^{3}$

The distance covered by a body moving with uniform acceleration is given by $s = u t + \frac{1}{2} a t^{2}$ As body starts from rest, therefore initial velocity u = 0 $∴$ Distance covered by the body $s = \frac{1}{2} a t^{2}$ or $s \propto t^{2}$