A body of mass m is lifted up from the surface of earth to a height three times the radius of the earth R . The change in potential energy of the body is

Question

A body of mass m is lifted up from the surface of earth to a height three times the radius of the earth R . The change in potential energy of the body is (A) 3mgR (B) (5/4)mgR (C) (3/4)mgR (D) 2mgR

Tardigrade Admin · Accepted Answer

Δ U=(m g h/1 + (h)R)=(m g × 3 R/1 + (3 R)R) =(3/4)mgR

Q. A body of mass $m$ is lifted up from the surface of earth to a height three times the radius of the earth $R$ . The change in potential energy of the body is

$3 m g R$

$\frac{5}{4} m g R$

$\frac{3}{4} m g R$

$2 m g R$

$Δ U = \frac{m g h}{1 + \frac{h}{R}} = \frac{m g \times 3 R}{1 + \frac{3 R}{R}}$
$= \frac{3}{4} m g R$

Q. A body of mass m is lifted up from the surface of earth to a height three times the radius of the earth R . The change in potential energy of the body is

3mgR

45​mgR

43​mgR

2mgR