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Q.
A body of mass $m$ is lifted up from the surface of earth to a height three times the radius of the earth $R$ . The change in potential energy of the body is
NTA AbhyasNTA Abhyas 2022
Solution:
$\Delta U=\frac{m g h}{1 + \frac{h}{R}}=\frac{m g \times 3 R}{1 + \frac{3 R}{R}}$
$=\frac{3}{4}mgR$