Question Error Report

Thank you for reporting, we will resolve it shortly

Back to Question

Q. A body of mass $m$ is lifted up from the surface of earth to a height three times the radius of the earth $R$ . The change in potential energy of the body is

NTA AbhyasNTA Abhyas 2022

Solution:

$\Delta U=\frac{m g h}{1 + \frac{h}{R}}=\frac{m g \times 3 R}{1 + \frac{3 R}{R}}$
$=\frac{3}{4}mgR$