For a gas CP-CV=R in a state P and CP-CV=1.10 R in a state Q, TP and TQ are the temperatures in two different states P and Q respectively. Then

Question

For a gas CP-CV=R in a state P and CP-CV=1.10 R in a state Q, TP and TQ are the temperatures in two different states P and Q respectively. Then (A) TP=TQ (B) TP < TQ (C) TP=0.9 TQ (D) TP >TQ

Tardigrade Admin · Accepted Answer

CP-CV=R for ideal gas and gas behaves as ideal gas at high temperature so TP > TQ

Q. For a gas $C_{P} - C_{V} = R$ in a state $P$ and $C_{P} - C_{V} = 1.10 R$ in a state $Q, T_{P}$ and $T_{Q}$ are the temperatures in two different states $P$ and $Q$ respectively. Then

$T_{P} = T_{Q}$

$T_{P} < T_{Q}$

$T_{P} = 0.9 T_{Q}$

$T_{P} > T_{Q}$

$C_{P} - C_{V} = R$ for ideal gas and gas behaves as ideal gas at high temperature
so $T_{P} > T_{Q}$

Q. For a gas CP​−CV​=R in a state P and CP​−CV​=1.10R in a state Q,TP​ and TQ​ are the temperatures in two different states P and Q respectively. Then

TP​=TQ​

TP​<TQ​

TP​=0.9TQ​

TP​>TQ​